If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.
Note: If the number is a multiple of both 3 and 5, only count it once. Also, if a number is negative, return 0(for languages that do have them)
def solution(number): sum = 0 if(number <= 0): return 0 else: for i in range(1,number+1): if( i % 3 == 0 or i % 5 == 0 and i % 15 != 0 ): sum += i return sum
There are 105 test cases for this challenge in codewars, 55 of them passes and 50 of them don’t. How can I improve my code?
p.s : I do not see which cases pass or which are do not.
p.s 2 : GUYS NOTHING CHANGES WHEN I REMOVE i % 15 != 0
Source: Python Questions