I was using binary search to find index of an item in a list. I used list.index() method for the same. I used time.time() to find out the time difference between the two algorithms. The result I got was binary search was 10000 times faster than list.index(). Why is that? Does list.index() follow linear search ..
New to algorithms Trying a Binary Search problem, below is my code – def search(nums, target): low = 0 high = len(nums) – 1 #a = sorted(nums) –> to sort the list if needed [ change nums to a ] while low <= high: middle = (low + high) // 2 if target == nums[middle]: ..
hey guys i am trying to learn this concept during my programming course and i am not being able to understand this concept so please help me with it by posting the answers to this question language :- Python . Source: Python..
I have already read through the answers on this question – Codility NailingPlanks. This is not a duplicate, as I’m trying to solve this problem using a different approach – instead of running a binary search on the planks that a given nail can cover, I’m trying to run it on the total number of ..
I’m trying to find the nth root with some specified accuracy by using binary search. Here is the code I have written: def root(n, number, accuracy): if number < 0: -1 * number low = 0.0 high = number guess = (low + high) / 2.0 while abs((guess ** n) – number) >= accuracy: if ..
I have tried to implement a binary search algorithm by myself in python and it worked but when I looked into the internet most of them did differently. I don’t know which one is better from these two My Binary Search Algorithm def binary_search(arr, item): minVal = 0 maxVal = len(arr) – 1 backtrack = ..
Hi I am doing DSA problems and found a problem called as ceiling of the element in sorted array. In this problem there is a sorted array and if the target element is present in the sorted array return the target. If the target element is not found in the sorted array we need to ..
I was trying to execute the Binary Search program in python. I followed the algorithm steps yet it gives me this error. Here’s my code: def binarySearch(a,k,l,r): if l > r: return -1 else: mid = (l+(r-l))//2 if(a[mid]>k): return binarySearch(a,k,l,mid-1) elif(a[mid]<k): return binarySearch(a,k,mid+1,r) else: return mid t = int(input("Enter no. of test cases: ")) for ..
I am given a sorted array that has been shifted to the right by some amount. For example [45,61,71,72,73,0,1,21,33,37] ; which is [0,1,21,33,37,45,61,71,72,73] shifted to the right by 5 spaces. We are also given a target integer that may or may not be in the array. If it is in the array, we are asked ..
For solving the question https://leetcode.com/problems/first-bad-version/. class Solution: def firstBadVersion(self, n): """ :type n: int :rtype: int """ l = 0 r = n while(l<r): mid = int(l +r/2) if (isBadVersion(mid)): r = mid else: l = mid+1 return l gives me a TLE. But when I change it to mid = int(l + (r-l)/2) it ..