Category : datetime

I have data which has a column contain time range as the example below: Time range (d/m/y) 0 1/1/2021 – 3/1/2021 1 6/1/2021 – 10/1/2021 2 15/1/2020 – 20/1/2021 Give a certain date such as 8/1/2021, how can I find the index of time range which contain this date in Python? Source: Python..

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I want my own serial no. Which is like this BILLNO20212201 where last two digits get increment automatically if fist serial no was BILLNO20212201 then second willbe BILLNO20212202 wise versa And this want to be save in database I generate code Bill_str = "BILLNO" today_date = str(today.day) today_year = str(today.year) Bill_no = Bill_str+today_date+today_year Print(Bill_no) How ..

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Refer code for datetime python module """Concrete date/time and related types. See http://www.iana.org/time-zones/repository/tz-link.html for time zone and DST data sources. """ __all__ = ("date", "datetime", "time", "timedelta", "timezone", "tzinfo", "MINYEAR", "MAXYEAR") import time as _time import math as _math import sys def _cmp(x, y): return 0 if x == y else 1 if x > ..

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