#### Category : datetime

Is there a simple way to convert numbers like 1030, 0131, 1231, etc to an mm-dd (or even mm-dd-yyyy assuming everything is 2020) format, so that I can perform date calculations with them? For example, I would like to be able to do (1231 minus 0131) = 11 months. Of course, I could just do ..

By using time.time() function, I am getting timestamps like this start = 1606594554.4789438 end = 1606594553.8903968 I want to find no of seconds between these timestamps in this format, ex:- 6.532 seconds (upto 3 decimals) I tried :- 1. a = (float(f)-float(s))*(60*60*24) 2. datetime.timedelta(0, c) :- But couldnt get output in desired format. Output : ..

I can do: df = pd.read_csv(usage_output, parse_dates=[[‘StartDate’, ‘StartTime’],[‘EndDate’, ‘EndTime’]]) I can also do: df = pd.read_csv(usage_output, parse_dates={‘TimeStamp_Start’: [‘StartDate’, ‘StartTime’]}) How to combine both, so that I have two parsed columns "TimeStamp_Start" and "TimeStamp_End"? I tried: df = pd.read_csv(usage_output, parse_dates=[{‘TimeStamp_Start’: [‘StartDate’, ‘StartTime’]}, {‘TimeStamp_End’: [‘EndDate’, ‘EndTime’]}]) Error ValueError: {‘TimeStamp_Start’: [‘StartDate’, ‘StartTime’]} is not in list Source: Python ..

I’m trying to get number of days between two dates using below function df[‘date’] = pd.to_datetime(df.date) # Creating a function that returns the number of days def calculate_days(date): today = pd.Timestamp(‘today’) return today – date # Apply the function to the column date df[‘days’] = df[‘date’].apply(lambda x: calculate_days(x)) The results looks like this 153 days ..

I have a GMT datetime: import datetime, pytz d = datetime.datetime(2020, 11, 27, 12, 0, 0) Given a "country+sate" or "country+city" pair (when state is not available) like this: #case 1 country, state = ‘US’, ‘CA’ #case 2 country, city = ‘RU’, ‘Nowosibirsk’ # here no information of "State" is given how to find the ..

I am trying to convert my string ‘Time’ to Time in Python but getting error Tried multiple things Not Working :- Python datetime formatting without zero-padding Code: dt[‘Time’] = pd.to_datetime(dt[‘Time’], format= ‘%H:%M:%S’, infer_datetime_format=True) Data: Ticker,Date,Time,Open,High,Low,Close,Volume,OpenInterest BANKNIFTY04JUN2023000CE.NFO,14/05/2020,13:00:59,65,65,65,65,20,0 BANKNIFTY04JUN2023000CE.NFO,14/05/2020,15:01:59,75,75,75,75,20,20 BANKNIFTY14MAY2013900PE.NFO,14/05/2020, 9:15:59,0.8,0.8,0.7,0.7,40,18860 Error: Traceback (most recent call last): File "<string>", line 1, in <module> File "C:UsersAnkuranaconda3libsite-packagespandascoretoolsdatetimes.py", line 728, ..

So I am trying to calculate the duration between two days but I just want the number of days instead of minutes and seconds for the duration. The code I am using is the following: df[‘duration’]=df[‘deadline’].sub(df[‘created_at’].astype(‘datetime64[D]’)) However, this gives me sth like : 35 days 12:42:40. But I don’t want the "days 12:42:40." Instead, I ..