1.I have a dataframe Input: emp data pp ab qq bc rr cs ss dp dictionary: df_r.to_dict(‘dict’) 2.I have another dataframe with name having string values: ID name 1 [‘u’][‘s’] 2 [‘v’][‘ab’] 3 [‘w’][‘dp’] 4 [‘x’][‘t’] dictionary : df.to_dict(‘dict’) Expected result : I want to replace the value of name as per data’s emp value ..
Category : dictionary
I am checking the dictionary key If key is present i am extracting role id = ‘L13’ li = [ { ‘id’: ‘L12’, ‘role’: ‘Owner’ }, { ‘id’: ‘L13’, ‘role’: ‘Owner’ } ] Code is below role = ” for each_element in li: if each_element[‘id’] == id: if each_element[‘role’] == ‘Owner’: #print(each_element[‘role’]) role = ‘Owner’ ..
I trying to create the below DataFrame, but not sure why it is giving me the below error: TypeError: ‘dict’ object is not callable df1 = pd.DataFrame({‘A’: [1, 1, 2, 3, 4], ‘B’: [3, 6, 3, 8, 9], ‘C’: [‘a’, ‘b’, ‘c’, ‘d’, ‘e’]}) df1 Source: Python..
In the following code, queryResult is a Nested Array and from which I am moving data to a dictionary by providing keys to each value with the help of nested for loop. But I am receiving error at value4[‘videoid’] = item[0] . The value4[‘videoid’] is key, and item[0] is an integer value and the rest ..
In the following code, queryResult is a Nested Lists. A nested list means all of the list values had another list. LIKE: [(1024, jkhsa97890),(1025, khka65757),(1025, kjhaksd87987), ….] So with the first loop, we are getting lists fromqueryResult and storing them in the record. ARRAYS STORED IN RECORD: (1024, jkhsasa97890) (1025, khkaada65757) (1025, kjhaksd87987) …. Then ..
I have a dictionary like that: dictionary = {‘user1’:[{‘product1’:10}, {‘product2’:15}, {‘product3’: 20}], ‘user2’:[{‘product1’:13}, {‘product2’:8}, {‘product3’: 50}]} I want to construct a dataframe where I can see user1 and user2 as indices, product1, product2 and product3 as columns and values of these products should be values of columns. I tried looking here and found this post ..
I have multiple dictionaries in one variable results. How to return only 1st dictionary value from that? for result in results: print(result) Output is : {‘Title’: ‘John’} {‘Title’: ‘Mark’} {‘Title’: ‘Adam’} {‘Title’: ‘Ethen’} {‘Title’: ‘Tom’} I want to return value of 1st dictionary ‘john’ Source: Python-3x..
this code worked fine and they print result in this format I need results in a nested dict format like this. please help me `data = { ‘year’: { ‘male’: {‘Q1’: 1, ‘Q2’: 1, ‘Q3’: 1, ‘Q4’: 1, }, ‘female’: { ‘Q1’: 1, ‘Q2’: 1, ‘Q3’: 1, ‘Q4’: 1, } } }` import csv results ..
I have a dictionary as a dataset which has the following form dataset {‘key1’: [{ ‘x1’: ‘…’, ‘x2’: ‘…’, ‘x3’: ‘…’ }], ‘key2’: […], ….} I want to extract 100 keys (random) as a txt file. I tried this code dataset.values().to_csv(‘result.txt’) but I have an error ‘dict_values’ object has no attribute ‘to_csv’ How can I ..
1.I have a dataframe Input: emp data pp ab qq bc rr cs ss dp I convert it into dictionary: df_r.to_dict(‘dict’) 2.I have another dataframe: ID name 1 s 2 ab 3 dp 4 t dictionary : df.to_dict(‘dict’) Expected result : I want to replace the value of name as per data’s emp value ID ..
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