EOF error is occurring in this step method, val = input().split(‘ ‘) value error occurs when I remove the try block from collections import deque n = int(input()) d = deque() for _ in range(n): try: method, val = input().split(‘ ‘) if method == ‘append’: d.append(val) if method == ‘appendleft’: d.appendleft(val) except ValueError: a = ..
Category : if-statement
I have a dataset with ‘Date’ and ‘Installs’, and I want to add a new column ‘Payout’. But the ‘Payout’ differs based on the ‘Date’ and ‘Installs. eg. 2021-04-09, 2 and in the ‘Payout’ column, should be $0.25 * 2 eg. 2021-04-22, 5 and in the ‘Payout’ column, should be $0.4 * 5 I have ..
In this code if a person if greater than 80 he/she should be displayed with different statement whereas the one with age greater than 18 different but if possible without adding anymore if statements if 80 > given > 18: print("you are eligible for voting") else: print("you are not") Source: Python..
When you run the code you should take a card from a set deck and from that I want it to display a write or wrong answer depending on if you type red or black by reading it, but no matter what I do it won’t run the if statement. import random class Card(object): def ..
I’m trying to make a program that checks username availability on Ubisoft.com. I tried to do this by entering a profile URL letting the code check whether the site gives a 200- or a 404 status code, with 404 being a Taken username and 200 an Available username. The problem with using a 200 status ..
I am converting this matlab code into Python but apparently I am making a small mistake that the results are not the same. Here is the matlab code: alpha = 0.1; beta = 0.01; Dt = 0.001; N = 1000; time = 0:Dt:40; state = zeros(length(time),N); R = rand(length(time)-1,N); for j = 1:N for i ..
I’ve read several other questions about this subject and my identation seems correct, I really dont understand why the code below is not working! import datetime def validate(date_text): if datetime.datetime.strptime(date_text, ‘%Y-%m-%d’): print(‘format is YMD’) elif datetime.datetime.strptime(date_text, ‘%Y-%d-%m’): print(‘format is YDM’) elif datetime.datetime.strptime(date_text, ‘%d-%m-%Y’): print(‘format is DMY’) elif datetime.datetime.strptime(date_text, ‘%m-%d-%Y’): print(‘format is MDY’) else: print(‘other’) validate(‘2003-12-23’) ..
I am writing a code where there is a ‘while loop’ that has an input that asks the user to choose one of the mentioned options. But I am having a problem that no matter what the user inputs, the if statement does the same output again and again. This is the code: while infinite ..
File1 1 14931 . A MQ=37;MQ0=0;DP=3;AN=4 GT:DP 0/0:. 1 14933 . G MQ=37;MQ0=0;DP=3;AN=4 GT:DP ./.:. 1 14934 . T MQ=37;MQ0=0;DP=3;AN=4 GT:DP ./.:. 1 14975 . C MQ=37;MQ0=0;DP=3;AN=4 GT:DP ./.:. 1 15021 . C AN=0 GT ./. 1 15211 . T MQ=37;MQ0=0;DP=3;AN=4 GT:DP ./.:. 1 15212 . T MQ=37;MQ0=0;DP=3;AN=4 GT:DP ./.:. File2 1 14933 rs199856693 G ..
Why does the if statement in the for loop not work properly? "0,1" is still being returned as True although it is smaller than 2. Code is a bit sloppy, sorry. def isprim(n): for i in range(2,n-1): if n % i == 0 or n < 2: return False return True for i in range(50): ..
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