Category : implementation

I’m trying to re-implement LDA with Gibbs sampling in Python 3.8, but my code gives wrong result. I’d highly appreciate if you are kind enough to help me debug the Gibbs sampling procedure! The code I adapted from was Agustinus Kristiadi’s Blog, which used the inference method instead of sampling. The naming of the parameters ..

I have idea to implement video conferencing in my helath care website project & I don’t know how to implement it. So it will be great favor to help Source: Python..

I am having some problems implementing the following equation in a performant way using Python: beta and gamma are cartesian coordinates {x,y} and b,m are some index value which can be quite big n=10000. I have a working version of the code which is shown below for the simple case of l=2 and m,b = ..

I have written a stack in python,and would like to remove all none implemented method that has be inherited from the deque class so that a stack instance may never call them. from collections import deque class Stack(deque): def __init__(self, iterable) -> None: self.iterable=iterable super().__init__(iterable=self.iterable) self.count = len(self.iterable) def clear(self): self.count = 0 return super().clear() ..

I am trying to implement the Crank-Nicolson method, which is described in Burden and Faires 10th edition as below: Observation: I was avoiding using images in the problem description, but could not think of a better way to present the steps. I tried fixing the code in the related question Crank-Nicolson Method, but was unable ..

import hashlib def xor(x, y): return bytes(x[i] ^ y[i] for i in range(min(len(x), len(y)))) def hmac_sha1(key_K, data): if len(key_K) > 64: raise ValueError(‘The key must be <= 64 bytes in length’) padded_K = key_K + b’x00′ * (64 – len(key_K)) ipad = b’x36′ * 64 opad = b’x5c’ * 64 h_inner = hashlib.sha1(xor(padded_K, ipad)) h_inner.update(data) ..

We are able to defeat the small integer intern in this way (a calculation allows us to avoid the caching layer): >>> n = 674039 >>> one1 = 1 >>> one2 = (n ** 9 + 1) % (n ** 9) >>> one1 == one2 True >>> one1 is one2 False How can you defeat ..