#### Category : multidimensional-array

I have numpy arrays a of shape (3, 4, 2) and b of shape (3, 2, 5). And I want the product of each row of a (of shape (4, 2)) by each row of b (of shape (2, 5)) and the result be a 3d array of shape (3, 4, 5). Of course I ..

Let’s say I have two lists of lists, a and b: a = [[1,2,3],[4,5,6]] b = [[7,8,9],[1,2,3]] If a and b were both lists of numbers, I could just convert them to arrays and obtain the sum a+b using Python. However, it seems I am unable to do the same if a and b are ..

Backgroup: I want to tranfer the binary bytes image to python services from other services with grpc protocol. and the python service will handle the image in opencv lib. I download the image from other serivces and send image data from memory to python services. The question is how to efficiently convert binary bytes image .. I have an adjacency matrix: [[0, 3, 4, 5, 2], [3, 0, 2, 4, -1], [4, 2, 0, 1, -1], [5, 4, 1, 0, -1], [2, -1, -1, -1, 0]] The position in the matrix, i.e., matrix[ i ][ j ] indicates an edge from vertex i to vertex j, and the value of matrix[ ..

I have a 1D list that has 2d elements which are frames of video, and I want to extract the consecutive static frames and consecutive frames that have moving objects in them. I have tried to get the Pearson correlation equation between a frame and the frames which are next to it if the correlation ..

When I read a CSV file, my data is in (1, 6000, 200) shape but I want data in (6000, 200, 6) shape. Is there any possible way in Python to convert this string [-9.3145 0.631 1.2924 -0.2776 -0.2061 -0.2084] into the third dimension? from glob import glob import numpy as np strain1 = glob("myfile.csv") .. I’m trying to generate a regular n number of points within the volume of a sphere. I found this similar answer (https://scicomp.stackexchange.com/questions/29959/uniform-dots-distribution-in-a-sphere) on generating a uniform regular n number of points on the surface of a sphere, with the following code: import numpy as np n = 5000 r = 1 z = [] y ..