This may sound like a stupid question but I had to ask. The following code checks whether a word entered by the user is a palindrome or not. When I use the below code, it says "This word is a Palindrome" for all the words. word = input("Enter a word for a Palindrome : ") ..
enter image description here I’m pretty stuck on this exercise, Does anyone have a direction? Source: Python..
i try to make program to find he length of the palindrome that can be made from a string in python, but i got wrong result. the program should: input: 5 wewewe pelatnas kedua di jogja and the output is length of string can be make palindrom: 5 3 1 1 3 this my program ..
I have found a recursive solution to check whether a linked list is a palindrome: def isPalindrome(self, head: ListNode) -> bool: self.front_pointer = head def recursively_check(head): if head: if not recursively_check(head.next): return False if self.front_pointer.val != head.val: return False self.front_pointer = self.front_pointer.next return True return recursively_check() After the ‘if head’ statement: Why are we returning ..
in the python code below, I need to use recursive functions to find all palindromic primes between two integers N, M, supplied as input. (start and endpoints are included). • A palindrome number is a number that reads the same from the front and the back. Examples are: 212, 44, 9009, 4567654. • To calculate ..
this is my code, but there is still an error, I will make the application determine whether the sentence is a palindrome or not a palindrome from tkinter import * class MembuatKolomTeks(Frame) : def __init__(self, master) : self.buatTeks() self.buatKolom(master) self.buatTombol() def buatTeks(self): Label(text="Inputkan Kalimat").grid(row=0) def buatKolom(self, master): self.kolom1 = Entry(master) self.kolom1.grid(row=0, column=1) def buatTombol(self): Button(text=’Hasil’, ..
def is_palindromic_linked_list(head): if head is None or head.next is None: return True slow = head fast = head while fast is not None and fast.next is not None: fast = fast.next.next slow = slow.next head_second_half = reverse(slow) #6, 4, 2 => 2, 4, 6 copy_head_second_half = head_second_half #<——HERE: copied linkedlist while (head is not None ..
The is_palindrome function checks if a string is a palindrome. A palindrome is a string that can be equally read from left to right or right to left, omitting blank spaces, and ignoring capitalization. Examples of palindromes are words like kayak and radar, and phrases like "Never Odd or Even". Fill in the blanks in ..
This is my current approach: def isPalindrome(s): if (s[::-1] == s): return True return False def solve(s): l = len(s) ans = "" for i in range(l): subStr = s[i] for j in range(i + 1, l): subStr += s[j] if (j – i + 1 <= len(ans)): continue if (isPalindrome(subStr)): ans = max(ans, subStr, ..
I am trying to find the longest Palidromic Substring of a given string, LeetCode problem. I am getting a lesser runtime for expanding centers even though its time complexity is N**2 and manachers is N. What mistake am I making? ”’ Manachers Algorithm O(N) —> runtime 2000ms class Solution(object): def addhashspace(self,s: str) -> str: t ..